Originally posted by Robbo
Now I want you to imagine something (much like the thought experiments employed by Einstein) imagine a beach ball being thrown, is it accurate ? Nope, and what of the ratio between volume (surface area) and weight?
The differential is large when compared to say a cannon ball of equal size where the ratio must be less but the cannon ball is inherently more accurate.
So it would seem the ratio between mass/ volume (surface area) does hold some practical significance when it comes to assessing relative accuracies.
Now am I playing devil’s advocate or do I have a point ?
Hee, hee, all will soon be revealed !!!
Robbo
Not convinced by the inertia argument, that one I really am struggling to remember, (something to do with resistance to changes in motion rather than continuation of momentum), so if the next bit is immediately proved wrong by a physisict out there so be it, I'm originally a Chemist by trade.
the mass to volume ratio you are referring to Robbo makes perfect sense if you are referring to mass divided by volume which is the density of the object rather than simply concentrating on surface area which is governed by the square-cube ratio, (more later).
A beach ball of exactly the same size as a cannon ball has a lower mass when compared to it's volume and is therefore easier to affect in terms of wind etc, as I recall this is due to it being able to be accellerated to a velocity V with less force because it suffers from less inertia, (less mass/volume or density), the problem with this would be that it's lower mass for the surface area results in less density and hence less resistance, (inertia again) to decelleration and/or directional movement and thus diminished range/accuracy. It also will have other problems such as distortion of surface shape under accelleration etc occuring making it inherently less accurate.
A cannon ball generally being a solid object has a larger mass for it's surface area and therefore has a greater inertial resistance to accelleration, putting it simply it takes more effort to fire it, (try throwing a cannon ball vs a beach ball of the same size). The advantage of a more dense round is that once it is moving its greater inertia means that it is less affected by negative accelleration and directional movement meaning that it takes more effort to get it there, but at least it will get there. The range of the shot is governed by the density of the object and the force used to propell it. If the mass M is constant between rounds they should, all other things being equal arrive at the same point at exactly the same time. Gravity overcomes inertia at roughly the same point if M and V are the same for each round, at which point the ball will begin a downward trajectory as well as a horizontal one.
I think this means that in terms of paintballs there has to be a balance between the density of the ball for a fixed volume sphere and the force needed to accellerate them.
Too much mass and the inertial force becomes higher and it requires more force to propell the round at the same velocity, the shell has to be thicker to cope with the higher energy at firing but the round should be less affected other forces during flight.
Lighter round, less energy require to overcome inertial force which means it can have a thinner shell, but it is more affected by other forces during flight.
So you have to trade off a degree of accuracy for the ability to break the ball on the target if the impact is at an equivalent velocity/force.
Originally posted by Robbo
isn't the surface area directly proportional to its volume ?
I think the surface area to volume ratio is governed by the square-cube ratio.
What this means is that as the surface area of an object increases by the square (E+2), the volume of the object increases by the cube, (E+3).
This is a quote from a book I was reading the other day that illustrates the problem here
If you doubled the diameter of the planet and the height of a man on it's surface, his mass would multiply by a factor of eight and the planet by a similar amount so his weight would be sixty four times as much as before. The problem with this is that the cross section of his legs would be only four times as much which means that the burden on his feet would be about sixteen times the prior burden - without strengthening his flesh. It's why ants cannot grow to the size of elephants without changing form radically
though it's just something I read and I'm assuming it's accurate but take no responsibility if it's not. Me just a thick ex-chemist management trainery type bod

and how you could apply this to a paintball I'm not sure as it's now far too late and I've worn out my brain cell.
Good discussion though
